Probability of having black, brown, red, blonde, auburn, hair color?

Increas

What is the probability of having:
⢠Black Hair
⢠Brown Hair
⢠red hair
⢠Blonde Hair
⢠Auburn Hair
⢠Brunette Hair

So far this is what I have:
P(red hair) = 1 - 2% of human population
2-6% of Europeans
10% of Irelander's
Down less than 1% in Asia and Africa
(Human population = 6.8 billion)

â If you can give me links, that would be helpful.

Thank you :)

Answer
here are some links that can be helpful
http://74.125.155.132/search?q=cache:l6GXDeU1GeQJ:www.purgatory.net/kornelia/1603/red_hair_facts.htm+hair+color+in+population&cd=11&hl=en&ct=clnk&gl=ca


Genetically, Africans have more variety than other races. Every time a group advanced out of Africa, or from one isolated area to another even more isolated, another batch of genetic variations was left behind. But on the surface, it's caucasians that have the most variety, for the simple reason that they have a lot less melanin, which takes the darkness out of their skin, hair, and eyes to reveal other possibilities.

Hair color is determined by 4 to 6 genes, each with several alleles, some with incomplete dominance (i.e. not a matter of one thing or the other, but perhaps a mix of both - like pink carnations). The basic genes involved are for black hair (with a recessive allele for not-black), one for brown hair (with a recessive for blond), and one for red hair (with a dominant allele for not-red). Some of these genes are close to eye color genes on chromosomes 15 and 19, and tend to go along with those genes, which is why we tend to see certain combinations of hair and eye color more frequently than others.

Black is the most common hair color in the world, and is due to a large amount of eumelanin. Brown is also common, and is due to eumelanin mixed with a bit of pheomelanin. Blond is only found in about 2% of the world's population. It is due to very small amounts of melanin. Slight amounts of black, brown, and red make for all the variations we see in blonds - such as ash, flaxen, and strawberry blond. And red hair is the rarest of all, about 1% of the world. It is due to high levels of pheomelanin plus low levels of eumelanin.

If you are curious, gray hair is due to nothing but a little black melanin, and white hair is a matter of no melanin at all.

light colored hair is found primarily in scandinavia and the baltic sea area. Blond and red hair was probably more common in Europe centuries ago (as witnessed by Greek and Roman accounts), but being recessive, it has slowly receded northward. But you can still find blonds and redheads in places like Afghanistan and northern Pakistan, where the descendents of Indo-European invaders live.

What is red-green color blindness?How to create a punnett square for it?

tulipsi

Please help me with following questions, I'm a non major doing biology and its hard but I try to do the way I can and compare my answer when I get a reply here...please please

1)Draw the punnett square for a heterozygous mother who carries the trait for red-green color blindness and a father without red-green color blindness.Make sure you indicate what chromosome the trait is on and thus the inheritance.Then determine the probability that the daughters fromt he cross would demonstrate red-green color blindness and the probability that the sons would demonstrate the trait.

2). Draw the punnet square cross between an AB blood type parent and a heterozygous A blood type parent and determine the probability that the children will be A,AB,B and O blood type.

3).Draw the punnett square and determine the probability for the autosomal recessive trait of gray haired flies in the offspring.One parent is homozygous dominant for black hair and the other parent is homozygous recessive for gray hair.

Please please help me..I have spent so much time figuring these out and I have answers but not quite sure..please

Answer
From the information in each question, you need to figure out the genotypes of the parents in each case.

So, for the first one, you know that colorblindness is X-linked. You also know that males have 1 X-chromosome and 1 Y, while females have 2 X-chromosomes. In the other two problems, the genes are not X-linked.

1) Let XB = normal vision allele and Xb = color blind allele. Mother is heterozygous so she would have a genotype XB Xb. The father has normal vision so he would be XB Y.

When you do the Punnett square, you should end up with All girls will have normal vision, but half of the girls will be carriers. For the sons, 1/2 will have normal vision and 1/2 will be colorblind.

2) One parent is IA IB and the other is IA i. In terms of genotypes, 1/4 of offspring will be IA IA, 1/4 will be IA i, 1/4 will be IA IB and 1/4 will be IB i. So, 1/2 of all kids will be type A, 1/4 will be B and 1/4 will be O.

3) Let G = normal and g = gray hair. The cross is between GG and gg, so all offspring will be Gg, and will have normal black hair.

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